In the following sequence of reactions:C_6H_5 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) $1$. $C_6H_5-NH_2$ reacts with $NaNO_2/HCl$ at $0-5 \ ^\circ C$ to form benzene diazonium chloride $(A)$,$C_6H_5N_2Cl$.$2$. $(A)$ reacts with $CuC

Vedclass · Accepted Answer

$C_6H_5-CH_2-OH$

Vedclass · Answer

(D) $1$. $C_6H_5-NH_2$ reacts with $NaNO_2/HCl$ at $0-5 \ ^\circ C$ to form benzene diazonium chloride $(A)$,$C_6H_5N_2Cl$.$2$. $(A)$ reacts with $CuCN$ (Sandmeyer reaction) to form benzonitrile $(B)$,$C_6H_5-CN$.$3$. $(B)$ undergoes catalytic hydrogenation with $H_2/Ni$ to form benzylamine $(C)$,$C_6H_5-CH_2-NH_2$.$4$. $(C)$ is a primary aliphatic amine,which reacts with $HNO_2$ $(NaNO_2/HCl)$ to form an unstable diazonium salt that decomposes to give benzyl alcohol $(D)$,$C_6H_5-CH_2-OH$.

In the following sequence of reactions:
$C_6H_5-NH_2$ $\xrightarrow[HCl]{NaNO_2} A$ $\xrightarrow{CuCN} B$ $\xrightarrow{H_2/Ni} C$ $\xrightarrow{HNO_2} D$
Product $(D)$ would be:

Similar Questions

Reduction of alkyl nitrites yields

The Hinsberg reagent is:

The major product obtained in the following reaction is:

The major products $A$ and $B$ from the following reactions are:

$C_2H_5Cl$ $\xrightarrow{KCN} X$ $\xrightarrow{H_2 / \text{Catalyst}} Y$ $\xrightarrow{CHCl_3 / KOH} Z$
What is '$Z$' in the above sequence of reactions?

Vedclass Test Series

Exam Paper Generator

Online Exam Module

In the following sequence of reactions:$C_6H_5-NH_2$ $\xrightarrow[HCl]{NaNO_2} A$ $\xrightarrow{CuCN} B$ $\xrightarrow{H_2/Ni} C$ $\xrightarrow{HNO_2} D$Product $(D)$ would be: